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计算[log9(5)+log3(5)]乘[log25(3)+log125(9)]

来源：学生作业帮 编辑：神马作文网作业帮 分类：数学作业 时间：2024/11/20 13:44:04
计算[log9(5)+log3(5)]乘[log25(3)+log125(9)]
计算[log9(5)+log3(5)]乘[log25(3)+log125(9)]
换底公式
=(lg5/lg9+lg5/lg3)(lg3/lg25+lg9/lg125)
=(lg5/2lg3+lg5/lg3)(lg3/2lg5+2lg3/3lg5)
=(1/2+1)*lg5/lg3*(1/2+2/3)*(lg3/lg5
约分
=(3/2)(7/6)
=7/4
(log4 3+log8 3)(log3 2+log9 2)-log1/2 32^1/3+5^(log25 9） (log4 3+log8 3)(log3 5+log9 5)(log5 2+log25 2)= （1）log4 27乘以log25 8乘以log9 5 （2）（log4 3+log8 3）（log3 2+log9 2 计算3∧log9(lg2-1)∧2+5log25∧(lg0.5-2)∧2 高中数学对数计算求值（log2 125+log4 25+log8 5）*（log125 8+log25 4+log5 2 2^(log4^12)-3^(log9^27)+5^(log25^1/3)等于多少? [log2 (125) +log4(25)+log8(5)][log125(8)+log25(4)+log5(2)] [log2 (125) +log4(25)+log8(5)][log125(8)+log25(4)+log5(2) (Log2 125+log4 25+log8 5)(log5 2+log25 4+log125 log3(5)+log9(5)求大神帮助 计算（log4 3+ log8 3）（log3 2+ log9 2）-- log1/2 32^(1/3)+5^（log2 2^log4底12减3^log9底27加5^log25底1/3的值