2xy+x+y=83,x+y=?
整数x,y满足方程2xy+x+y=83,则x+y怎么算
已知x*x-4xy+4y*y=0 求[2x(x+y)-y(x+y)]/(4x*x-4xy+y*y)的值?
x^2+xy+x=36,y^2+xy+y=20,求x+y.
如果x^2+xy+y-14,y^@+xy+x=28,求x+y的值.
(-3x^y+2xy)-( )=4x^+xy
f(x+y,xy)=x^2+y^2
已知x+y=-1,xy=-2,求代数式-5(x+y)+(x-y)+x(xy+y)的值
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已知3x*+xy-2y*=0,求(x/y)-(y/x)-(x*+y*)/(xy)的值.*是平方
已知x/y=2,求2x(x+y)-y(x+y)/4x²-4xy+y²
[-(x-y)^2/xy]^-4*(y^2-xy/x)^3*(x^4/y^10)÷(xy-y^2/x)^-5=-y(y-
已知3x^2+xy-2y^2=0,求{(x+y)/(x-y)+4xy/(y^2-x^2)}/{(x+3y)*(x-y)}