f(x)为多项式满足方程xf"(x)+(1-x)f'(x)+3f(x)=0,f(0)=1,求f(x)
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已知f(x)满足2f(x)+f(1/x)=3x,求f(x)?
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已知函数f(x)可导,且f(1)=1 若f(x)满足方程f(x)+xf'(x)=0,求f(2)
函数f(x)满足2f(x)+xf(-x)=x²+1,求f(x)解析式.
f(x)=x+积分符号1到0,xf(x)dx,求f(x)
设当x>0时,函数f(x)连续且满足f(x)=x+∫(1,x)1/xf(t)dt,求f(x)
设函数可导,且满足xf'(x)=f'(-x)+1,f(0)=0 求f'(x) 求f(x)的极限
设函数f(x)满足f(x)+2f(1/x)=x,求f(x)
设f(x)为连续函数,且满足f(x)=3x^2-x∫(1,0)f(x)dx求f(x)