2(x-1)²+▏x+2y+1▕=0,求½x²ºº³y
若|x+y-1|+(x-y-2)²=0,求代数式(x+2y)(x-2y)-(2x-y)(-y-2x)的值.
若|x+2y-1|+y²+4y+4=0,求(2x-y)²-2(2x-y)(x+2y)+(x+2y)&
已知|x+y+2|+(2x-3y-1)²=0 求 ⑴x、y的值 ⑵2x³-x²-3y
已知x²+y²+5=2x+4y,求【2x²-(x-y)(x-y)】【(x+y-1)(x-y
已知实数x,y满足x²+y²-xy+2x-y+1=0 求x y
若x、y满足2x+y=6,x-3y=1,求7y(x-3y)²-2(3y-x)³的值
2x²+1/2y²-2x-3y+5=0,求(2x√9x-y²√x/y³)-(√1
已知x²+y²+5=2x+4y,求代数式(2x²-(x+y)(x-y))x((x+y-1)
已知方程组2x+y=6 x-3y=1,求7y(x-3y)²-2(3y-x)³的值
(1)已知x+y=6,x²-y²=5,求x-y的值(2)若x+y=3,x²+y²
已知x²+|y+x|=x-1/4,求(3x+y)²(2x-y)²-(4x²+y&
1/2 x²y·( )=2x³y-x²y²