神马作文网帮个忙 求你们了 急用
来源：学生作业帮 编辑：神马作文网作业帮 分类：数学作业 时间：2024/11/18 16:20:58
帮个忙 求你们了 急用
xy²/(x²y-y) × x²/(x²+x)=
(x²-3x)/(x²-5x) × 2x-10/(x²-6x+9)=
化简求植
x²-1/(x²-x-2)除以x/2x-4,其中x=1/2
[x-x/(x+1)]除以[x/(2x-4)] ,其中x=√2+1
xy²/(x²y-y) × x²/(x²+x)=
(x²-3x)/(x²-5x) × 2x-10/(x²-6x+9)=
化简求植
x²-1/(x²-x-2)除以x/2x-4,其中x=1/2
[x-x/(x+1)]除以[x/(2x-4)] ,其中x=√2+1
xy²/(x²y-y) × x²/(x²+x)=xy²/[(x+1)(x-1)y]×x²/[x(x+1)]=x²y/[(x+1)²(x-1)]
(x²-3x)/(x²-5x) × 2x-10/(x²-6x+9)=x(x-3)/[x(x-5)]× 2(x-5)/(x-3)²=2/(x-3)
x²-1/(x²-x-2)=(x+1)(x-1)/[(x-2)(x+1)]=(x-1)/(x-2),将x＝1/2代入,得（1/2-1）/（1/2-2）＝1/3
[x-x/(x+1)]/[x/(2x-4)] ＝[x(x+1)-x]/(x+1)× [2(x-2)/x]=2x(x-2),将x=√2+1代入得
2*（√2+1）（√2+1-2）＝2*（√2+1）（√2-1）＝2
(x²-3x)/(x²-5x) × 2x-10/(x²-6x+9)=x(x-3)/[x(x-5)]× 2(x-5)/(x-3)²=2/(x-3)
x²-1/(x²-x-2)=(x+1)(x-1)/[(x-2)(x+1)]=(x-1)/(x-2),将x＝1/2代入,得（1/2-1）/（1/2-2）＝1/3
[x-x/(x+1)]/[x/(2x-4)] ＝[x(x+1)-x]/(x+1)× [2(x-2)/x]=2x(x-2),将x=√2+1代入得
2*（√2+1）（√2+1-2）＝2*（√2+1）（√2-1）＝2