(x+2)/(x²-2x)-(x-1)/(x²-4x+4),化简
化简{x²-2x分之x+2-x²-4x+4x分之x-1}除以X分之(x-1)(X-4)乘以(2-x)
[(x+2)/(x²+2x)-(x-1)/(x²-4x+4)]÷(x-4)/x
计算(x²+4x-12/x²+x+1)(x²-1/x²-4x+4)(2-x/x&
先化简再求值:(x+2/x²-2x - x-1/x²-4x+4)÷ x-4/x,其中x=3/2
先化简,再求值:[(x-2/x²+2x)-(x-1/x²+4x+4)]÷﹙x-4/x+2﹚,其中x&
(1)(1/x三次-1/x平方)*x平方/x-1 (2)(x/2-x )- (4-x²/x²+4x+
2道分式计算[(x+4)(x-2)]/x³+2x²+x÷[(x-2)/x·(x+4)/(x+1)]2
计算:(1)x²/x-2 - 4x/x-2 + 4/x-2;
计算 ∫(x^4-2x^3+x^2+1)/x(x-1)² dx
3X+(X+2)+(X+1)*(X-1)=4*(X²+8)
(x-1)^3(x+1)(x-2)/(x+4)
(x+1)(x+2)(x+3)(x+4)+1