5a+{3b+[6c-2a-2(a-c)]}-[9a-(7b+c)]
5a-{-3b+[6c-2a-(a-c)]}-[9a-(7b+c)]
已知a-b/2=b-2c/3=3c-a/4.求5a+6b-7c/4a-3b+9c
(a-b)(b-c)(c-a)/(b-a)(a-c)2(c-b)3
已知a+b/a-b=b+c/2(b-c)=c+a/3(c-a),求证:8a+9b+5c=0
(a+b)/(a-b)=(b+c)/2(b-c)=(c+a)/3(c-a),abc互不相等,证8a+9b+5c=o
{A+2B-3C=4,5A-6B+7C=8}求代数式A:B:C 2A-3C/A+2B
(a+b-c)^5(a-b-c)^2(c-a-b)^4(c+b-a)^3 计算
a-b=5,b-c=3,(c-a)(2b-a-c)=
b/(a+c)=1/2,a/(b+c)=1/5 怎么得出a/(a+b+c)=1/6,b/(a+b+c)=1/3?
a、b、c互不相等,则2a-b-c/(a-b)(a-c)+2b-c-a/(b-c)(b-a)+2c-a-b/(c-a)(
行列式证明|b+c c+a a+b| | a b c||a+b b+c c+a| = 2 |c a b||c+a a+b
计算(a-b)(a-c)/(a+b-2c)(a+c-2b)+(b-c)(b-a)/(b+c-2a)(b+a-2c)+(c