lim(x-0)(x+1)ln(1+x)/x^2+3x

来源：学生作业帮编辑：神马作文网作业帮分类：数学作业时间：2024/10/03 04:30:36

lim(x-0)(x+1)ln(1+x)/x^2+3x
利用等价无穷小替换，

当x-->0,ln(x + 1) x
lim(x-->0) (x + 1)ln(x + 1)/(x² + 3x)
= lim(x-->0) [(x + 1)x]/[(x + 3)x]
= lim(x-->0) (x + 1)/(x + 3)
= (0 + 1)/(0 + 3)
= 1/3

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