2(sin^4 x + cos^4 x) =1 [ - pi ≤ x ≤ pi ]

已知函数f（x）=cos（2x-pi/3）+2sin（x-pi)*sin(x+pi/4) a*sin(pi/4 - x) - b*cos(pi/4 - x) = a*sin(pi/4 + x) - b*cos( 若sin((pi/6)+x)=1/3,则cos((pi/3-x)=?cos((2pi/3)+x)=? 已知Sin(2x+pi/3)=1/3,求Sin(5Pi/6-4x), sin x + cos x = √2 * sin (x + Pi/4) 已知cos(x)=sqrt(10)/10,x属于(0,pi/2),求sin(pi/4+2x)的值 为什么y=2sin(3x-3/4 *pi) 可以写成y=-cos(3x+3/4 *pi) sin(x)/(1+cos(x))= -1 -pi小于等于x小于等于pi 函数f(x)=sin^2(x+pi/12)+cos^2(x-pi/12)的最大值 x=4*sin(2*pi*0.01*t).*sin(2*pi*3*t)+2*cos(pi*t*t/4);在matlab中 Matlab u(x,t)=sin(5*pi*x)cos(5*pi*t)+2sin(7*pi*x)cos(7*pi*t) 化简sin(x+PI/3)+2sin(x-PI/3)-根号3*cos(2pi/3-1)