若α+β=kπ+π/4,k∈Z,求(1+tanα)(1+tanβ)
已知α,β≠kπ+π/2 K∈Z ,3sin(α+β)-2=0,5sin(α-β)-1=0,求tanα/tanβ的值
已知tanα=2 若α是第三象限角,求sin(kπ-α)+cos(kπ+α)(k∈z)的值
已知sin(π-α)-cos(-α)=1/5,求tan[(2k+1)π+α]+cot[(2k+1)π-α](k属於Z)的
已知sinα=4sin(α+β),α+β≠kπ+π/2(k∈Z).求证tan(α+β)=sinβ/(cosβ-4)
3sinβ=sin(2α+β),α≠2kπ+π/2 ,α+β≠kπ+π/2 (k∈z)求证tan(α+β)=2tanα
已知α∈(2kπ+π/2,2kπ+3π/2),k∈z,且tan(3π/2-α)=1/3,分别求tan2α,sinα,si
求函数y=tan(-x-(π,5))(k∈Z)的单调减区间?
若α∈(-π/2+2kπ,2kπ)(k∈Z),则sinα,cosα,tanα的大小关系是
怎么证明tan(π/(2k+1))×tan(2π/(2k+1))×tan(3π/(2k+1))×.tan(k/(2k+1
【数学命题条件问题】命题:tan(α+β)=1是命题:α+β=kπ+π/4(k为整数)的什么条件?
求值tan(kπ+π/6)cos(kπ-4π/3),k属于z
已知2sin^α+sin2α/1+tanα=k(π/4