Block A has a mass of 3 kg and Block B has a mass of 5 kg.Ju
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Block A has a mass of 3 kg and Block B has a mass of 5 kg.Just before colliding,Block A has a speed of 4 m/s and Block B is at rest(0m/s).After the collision,Block B has a speed of 3m/s in the same direction that Block A was initially.What is the speed of Block You may notice you get a negative answer.What does that mean?
物体A质量为3kg,物体B质量为5kg,碰撞之前物体A速度为4 m/s,物体B此时静止.碰撞后,B物体具有与A物体初始速度方向相同的速度,其大小为3m/s,求此时A的速度?你会得到一个负数答案,那意味着什么呢?
假设A的速度为x m/s,方向与初始速度方向一致
根据动量守恒,则有 3*4 = 3x + 5*3
解得 x= -1 即此时A的速度为1m/s,方向与初始速度方向相反
注意:这时候两个物体的动能 0.5*5*3^2 + 0.5*3*1^2 = 0.5*48 =24
而A的初始动能 0.5*3*4^2 = 0.5*48 =24
这意味着物体A与B发生了完全弹性碰撞,能量没有损失
假设A的速度为x m/s,方向与初始速度方向一致
根据动量守恒,则有 3*4 = 3x + 5*3
解得 x= -1 即此时A的速度为1m/s,方向与初始速度方向相反
注意:这时候两个物体的动能 0.5*5*3^2 + 0.5*3*1^2 = 0.5*48 =24
而A的初始动能 0.5*3*4^2 = 0.5*48 =24
这意味着物体A与B发生了完全弹性碰撞,能量没有损失
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