char*s="abcde";s+=2;printf("%d",s),求结果

#include main() { char *p="abcde\ofghjik\0"; printf("%d\n",s main(){ char *s,*s1="Here";s=s1;while(*s1)s1++;printf("%d\n" main() { char s[]="\\141\141abc\t" ; printf("%d",strlen(s)); char s[]=" an apple" ; printf(" %d\n",strlen(s)); A)7 B)8 C) #include main() {char *s={"abc"}; do { printf("%d",*s%10); + main() { char s[]="stop\0\n\""; printf("%d\n",strlen(s)) } 设有定义：char s[12]={"string"};则printf("%d",strlen(s));的输出值是多少? Char s[]="\113vwxyz\x41"; printf("%d\n",strlen(s)); 为什么结果是7 C语言题目求解char[ ]="\t \chinese\ \girl\n" printf("%d",strlen(s)) 设有一下程序 int x=0 ,s=0; while(!=0)s+=++x; printf(''%d'',s);求结果 printf("%s%s%s%d%d%d\n",printf("\n"); char *p[12]={1,2,3,4,5,6,7,8,9,10,11,12}； printf("%s\n",*(p+