limAn=C,limBn=D,D#0.so:lim(An/Bn)=C/D XXX why
设limAn=a,limBn=b,试证明:lim{(A1*Bn+A2*Bn-1+...+An*B1)\n}=ab (n-
lim(an+1-an)=d,求证lim(an/n)=d
( )-(c-d)=(a-c)-(-b+d)
求证极限:设数列{An},{Bn}均收敛,An=n(Bn-Bn-1),求证limAn = 0.
已知数列{An}与{Bn}都是公差不为零的等差数列,且limAn/Bn=2,求lim(A1+A2+……+An)/(n*B
若liman=a,则lim|an|=|a|
设an,bn都是等差数列,其中a1=3,b1=2,b2是a2与a3的等差数列,liman/bn=1/2,求lim(1/a
a>b>c>d>0.a/b=c/d怎么证明a+d>c+b
已知数列{An}与{Bn}都是公差不为零的等差数列,且limAn/Bn=3,求lim(B1+B2+……+B2n)/(n*
已知数列{an}、{bn}都是公差不为零的等差数列,且liman/bn=3,求lim(b1+b2+……b3n)/(n*a
实数a,b,c,d满足d>c;a+b=c+d;a+d
lim(5n-根号(an^2+bn+c))=2,求实数a,b,c