已知数列{an}满足an+an+1=12
若数列{An}满足An+1=An^2,则称数列{An}为“平方递推数列”,已知数列{an}中,a1=9,点(an,an+
已知数列{an}满足an+1=an+n,a1等于1,则an=?
已知数列{an}满足an+1=2an+3.5^n,a1=6.求an
已知数列{an}满足a1=1,a2=2,an+2=an+an+12,n∈N*.
已知:等差数列,满足an+an+1+an+2=4则该数列为递增数列
已知数列an满足a1=1,1/an+1=根号1/an^2+2,an>0,求an
已知数列{an}满足a1=1,a2=3,an+2=3an+1-2an求an
已知数列an满足 a1=1/2,an+1=3an/an+3求证1/an为等差数列
已知数列{an}满足a1=2,an+1-an=an+1*an,那么a31等于
已知数列{an}满足a1=2,an+1=2an/an+2,则an等于多少
已知数列{an}满足a1=1/2,an+1=3an+1,求数列{an}通项公式
已知数列{An}满足A1=1,An+1=2An+2^n.求证数列An/2是等差数列