解x+y/3+x-y/2=2① 4(x+y)-7(x-y)=-2 ②
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解x+y/3+x-y/2=2① 4(x+y)-7(x-y)=-2 ②
过程………………
过程………………
答:
(x+y)/3+(x-y)/3=2
4(x+y)-7(x-y)=-2
设a=x+y,b=x-y,方程组化为:
a/3+b/3=2…………(1)
4a-7b=-2…………(2)
(1)*12-(2)得:
4a-4a+4b+7b=24+2
11b=26
b=26/11
代入(2)得:
4a-182/11=-2
4a=(182-22)/11
4a=160/11
a=40/11
所以:
a=x+y=40/11
b=x-y=26/11
两式相加:2x=66/11=6,x=3
代入a得:a=3+y=40/11
解得:y=7/11
所以:x=3,y=7/11
再问: 是(x+y)/3+(x-y)/2=2 4(x+y)-7(x-y)=-2 能不能重新算一下,谢谢
再答: sorry,我以为还是原来的题目: 答: (x+y)/3+(x-y)/2=2 4(x+y)-7(x-y)=-2 设a=x+y,b=x-y,方程组化为: a/3+b/2=2…………(1) 4a-7b=-2…………(2) (1)*12-(2)得: 4a-4a+6b+7b=24+2 13b=26 b=2 代入(2)得: 4a-14=-2 4a=12 a=3 所以: a=x+y=3 b=x-y=2 两式相加:2x=5,x=5/2 代入a得:a=5/2+y=3 解得:y=1/2 所以:x=5/2,y=1/2
(x+y)/3+(x-y)/3=2
4(x+y)-7(x-y)=-2
设a=x+y,b=x-y,方程组化为:
a/3+b/3=2…………(1)
4a-7b=-2…………(2)
(1)*12-(2)得:
4a-4a+4b+7b=24+2
11b=26
b=26/11
代入(2)得:
4a-182/11=-2
4a=(182-22)/11
4a=160/11
a=40/11
所以:
a=x+y=40/11
b=x-y=26/11
两式相加:2x=66/11=6,x=3
代入a得:a=3+y=40/11
解得:y=7/11
所以:x=3,y=7/11
再问: 是(x+y)/3+(x-y)/2=2 4(x+y)-7(x-y)=-2 能不能重新算一下,谢谢
再答: sorry,我以为还是原来的题目: 答: (x+y)/3+(x-y)/2=2 4(x+y)-7(x-y)=-2 设a=x+y,b=x-y,方程组化为: a/3+b/2=2…………(1) 4a-7b=-2…………(2) (1)*12-(2)得: 4a-4a+6b+7b=24+2 13b=26 b=2 代入(2)得: 4a-14=-2 4a=12 a=3 所以: a=x+y=3 b=x-y=2 两式相加:2x=5,x=5/2 代入a得:a=5/2+y=3 解得:y=1/2 所以:x=5/2,y=1/2
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