一,((X-5)*X^2/3)的导数是怎么推导为(5/3X^2/3)-(10/3X^-1/3)的.

来源：学生作业帮编辑：神马作文网作业帮分类：数学作业时间：2024/11/12 03:18:24

一,((X-5)*X^2/3)的导数是怎么推导为(5/3X^2/3)-(10/3X^-1/3)的.
就一步一步来啊
[(x-5)*(x^2/3)]'
=(x-5)'*(x^2/3)+(x-5)*(x^2/3)'
=1*(x^2/3)+(x-5)*(2/3)*x^[(2/3)-1]
=x^(2/3)+(x-5)*(2/3)*x^(-1/3)
=x^(2/3)+(2/3)x^(2/3)-(10/3)x^(-1/3)
=(5/3)x^(2/3)-(10/3)x^(-1/3)

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