神马作文网1.-10+10x^2/x^3+2x^2-x-2 约分
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1.-10+10x^2/x^3+2x^2-x-2 约分
2.已知y/x=5/3,求3x^2-5xy+2y^2/2x^2+3xy-5y^2的值
2.已知y/x=5/3,求3x^2-5xy+2y^2/2x^2+3xy-5y^2的值
-10+10x^2/x^3+2x^2-x-2
=10(x^2-1)/[x^2(x+2)-(x+2)]
=10(x^2-1)/[(x+2)(x^2-1)]
=10/(x+2)
y/x=5/3
所以y/5=x/3
令y/5=x/3=k
y=5k
x=3k
(3x^2-5xy+2y^2)/(2x^2+3xy-5y^2)
=(3x-2y)(x-y)/(2x+5y)(x-y)
=(3x-2y)/(2x+5y)
=(9k-10k)/(6k+25k)
=-k/31k
=-1/31
=10(x^2-1)/[x^2(x+2)-(x+2)]
=10(x^2-1)/[(x+2)(x^2-1)]
=10/(x+2)
y/x=5/3
所以y/5=x/3
令y/5=x/3=k
y=5k
x=3k
(3x^2-5xy+2y^2)/(2x^2+3xy-5y^2)
=(3x-2y)(x-y)/(2x+5y)(x-y)
=(3x-2y)/(2x+5y)
=(9k-10k)/(6k+25k)
=-k/31k
=-1/31