y=2x-75x+3y+2z=23x-4z=44x+9y=123y-2z=17x+5z=19/4
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
x/2=y/3=z/5 x+3y-z/x-3y+z
x=y/z=z/3,x+y+z =12,求2x+3y+4z是多少,
三元一次计算练习题x-2y=-9y-z=32z+x=47y=2x-75x+3y+2z=23x-4z=44x+9y=123
(x+y-z)(x-y+z)=
(4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuai
已知3x-2y-5z=0,2x-5y+4z=0,且x,y,z均不为0,求3x*x+2y*y+5z*z/5x*x+y*y-
x+2y+4z=17 2x+y+z=7 3x+y+2z=11
2x-y+2z=-17 3x+y-3z=-4 x+y+z=6
2x+5y+4z=6,3x+y-7z=-4,x+y-z=?
{2x+3y-4z=-5 x+y+z=6 x-y+3z=10
2x+5y+4z=0,3x+y-7z=0,则x+y-z=?