如何解x+y>11,10x+y-18=10y+x

解方程组:2/(x+y)+5/(x-y)=18 9/(x+y)-10/(y-x)=66 解方程组：2/(x+y)+5/(x-y)=18 9/(x+y)-10/(y-x)=66 已知/x/+x+y=10,/y/+x-y=12.求x+y的值 已知2x-y=10,求[(x²+y²)-(x-y)²+2y(x-y)]/4y X+Y=7(100X+Y)-(10Y+X)=(10Y+X)-(10X+Y) 如何使用配方发解方程X^2 + Y^2 - 2X + 10Y = -22 已知实数x,y满足|x|+x+y=10、x+|y|-y=12,则x+y的值? 用加减法解方程组:{(x+y)/6+(x-y)/10=3 (x+y)/6+(y-x)/10=-1 解方程组x+y/6+x-y/10=3,x+y/6+y-x/10=-1 解方程组:(x+3)(y-2)=(x-3)(y+10),(x+1)(y+3)=(x-2)(y+12) 解方程组 2x+y(y-2x)=9 (x+y)(x+y-3)=10 解方程组 10（x-y)=3(x+y)+15 6(x+y)=4(2x-y)+16