2010x+2011y=2013 2011x+2012y=2010 x=?y=?
[x(x-y)-y(x-y)+(x+y)(x-y)]÷2x其中x=2012 y=2013
已知(2011+y-x)(x-y-2009)=-2010,求(2011+y-x)²+(2009+y-x)&su
化简(2x^3y^3+x^4y^2+x^2y^4)^2-x^2y^2(x+y)^2,x=2012,y=-2011
x(x+y)-(x-y)(x+y)-y^2,其中x=(1/4)的2010次方,y=4的2011次方
已知:x+2y=2011 求代数式{(x^+y^)-(x-y)^+2x(x+y)}/2x的值
二元函数f(x,y)=x+y/x-y,求f(y/x,x/y)
先化简,再求值:[(x-y)2+(x+y)(x-y)]÷2x.其中x=2011,y=2010.
现化简,再求值:【(x-y)的平方+(x+y)(x-y)】除以2x,其中x=2011,y=2010
先化简,再求值 (1)[(x-y)的平方+(x+y)(x-y)]÷2x 其中X=2010,y=2009 (2)y(x+y
当x-y/x+y=2009/2010时,求代数式2009(x+y)/x-y+4020(x-y)/x+y的值.
若x-y=1,求代数式x(x-y)+y(y-x)+2013的值
) y=cos(x-y)