arcsin[sin(19Π/12)]求值
反函数求值tan[arcsin(-1/4)+π/3]
求值:sin(π/12)+cos(π/12)
求值:⑴sin(-19π/3)*cos(19π/6)
不查表求值:cos5π/12·sinπ/12=
反三角函数求值arccos(cos5π/4)=?arctan(tan4π/3)=?arcsin(sin6)=?
求值tan(arcsin√2/2)
求值:cos(arcsin√3/2)=
tan{arcsin[cosπ/4]+arccos[sinπ/3]+arctan√3}
arcsin(sinx)与sin(arcsinx)
求值:sin(π/4)cos(19π/6)tan(21π/4)急!
求值:sin(-3分之19π)+cos(-6分之25π)=?
利用二倍角公式求值sin(π/12)cos(π/12)