求证:tanxsinx/(tanx-sinx)=(tanx+sinx)/(tanxsinx)
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求证:tanxsinx/(tanx-sinx)=(tanx+sinx)/(tanxsinx)
两边同时乘以(tan(x)sin(x))/(tan(x)+sin(x)),可得原命题即证明
tan(x)tan(x)sin(x)sin(x)/( tan(x)tan(x)-sin(x)sin(x))=1
tan(x)tan(x)sin(x)sin(x)/( tan(x)tan(x)-sin(x)sin(x))分子分母同时除以
sin(x)sin(x)可得:
tan(x)tan(x)/( 1/(cos(x)cos(x))-1)=tan(x)tan(x)/tan(x)tan(x)=1=右边,证毕
tan(x)tan(x)sin(x)sin(x)/( tan(x)tan(x)-sin(x)sin(x))=1
tan(x)tan(x)sin(x)sin(x)/( tan(x)tan(x)-sin(x)sin(x))分子分母同时除以
sin(x)sin(x)可得:
tan(x)tan(x)/( 1/(cos(x)cos(x))-1)=tan(x)tan(x)/tan(x)tan(x)=1=右边,证毕
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