{[sin(π-α)-cosα]^2}/{cot[(3π/2)+α]} - 2cos(α+5π/6)*cos(α-5π/
化简cos(α-π)cot(5π-α)/tan(2π-α)sin(-2π-α)
化简sin^2(α+π)cos(π+α)cot(-α+2π)/tan(π-α)cos^3(-α-π)
1)求证cotαcosα/cotα-cosα=tan(α/2+π/4)
sin^2α*tanα+cos^2α*cotα-2sinα*cosα(π-α)
已知(sinα+cosα)/(sinα-cosα)=3,求[sin²(2π-α)+cot(3/2*π-α)]/
已知tan(π/4+α)=-3,求[2(Sinα)的平方+3SinαCosα]/(Cotα-SinαCosα)的值.
cos(α-3π/2)=1/5,求sinα*cotα α是第三象限角.
【sin(α+2kπ)+cos(π/2+α)+tan(3π-α)】/【sin(α-π)+cos(α-π/2)+cot(π
已知cot(π/4+α)=-1/3,则sin方α+sinαcosα-2cos方α等于
化简[sin(π-α)tan(5π/2+α)]/[cos(2π-α)cot(π/2-α)]
cos(α-π)cot(5π-α)/tan(2π-α)sin(-2π-α) 急昂
化简sin(α-5π)/cos(3π-α)×cos(π/2-α)/sin(α-3π)×cos(8π-α)/sin(-α-