已知|a-1/2|+(b+2)^2=0求a^3-3a^2b+4ab^2-2b^2
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已知|a-1/2|+(b+2)^2=0求a^3-3a^2b+4ab^2-2b^2
|a-1/2|+(b+2)^2=0
|a-1/2|>=0
(b+2)^2>=0
所以
|a-1/2|=0
(b+2)^2=0
a=1/2
b=-2
a^3-3a^2b+4ab^2-2b^2
=(a-b)^3+ab^2-b^2
=125/8-2+4
=141/8 再答: |a-1/2|+(b+2)^2=0 |a-1/2|>=0 (b+2)^2>=0 所以 |a-1/2|=0 (b+2)^2=0 a=1/2 b=-2 a^3-3a^2b+4ab^2-2b^2 =(a-b)^3+ab^2-b^2 =125/8-2+4 =141/8
再答: |a-1/2|+(b+2)^2=0 |a-1/2|>=0 (b+2)^2>=0 所以 |a-1/2|=0 (b+2)^2=0 a=1/2 b=-2 a^3-3a^2b+4ab^2-2b^2 =(a-b)^3+ab^2+b^3-2b^2 =125/8-2+4-8 =61/8
|a-1/2|>=0
(b+2)^2>=0
所以
|a-1/2|=0
(b+2)^2=0
a=1/2
b=-2
a^3-3a^2b+4ab^2-2b^2
=(a-b)^3+ab^2-b^2
=125/8-2+4
=141/8 再答: |a-1/2|+(b+2)^2=0 |a-1/2|>=0 (b+2)^2>=0 所以 |a-1/2|=0 (b+2)^2=0 a=1/2 b=-2 a^3-3a^2b+4ab^2-2b^2 =(a-b)^3+ab^2-b^2 =125/8-2+4 =141/8
再答: |a-1/2|+(b+2)^2=0 |a-1/2|>=0 (b+2)^2>=0 所以 |a-1/2|=0 (b+2)^2=0 a=1/2 b=-2 a^3-3a^2b+4ab^2-2b^2 =(a-b)^3+ab^2+b^3-2b^2 =125/8-2+4-8 =61/8
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