(4x-1)÷3-(x-2)÷6=(4+x)÷2 怎么解
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(4x-1)÷3-(x-2)÷6=(4+x)÷2 怎么解
(1)(4x-1)÷3-(x-2)÷6=(4+x)÷2 (2)x/3-x/5=4 (3)(y+2)÷4-(y-3)÷5=10
(1)(4x-1)÷3-(x-2)÷6=(4+x)÷2 (2)x/3-x/5=4 (3)(y+2)÷4-(y-3)÷5=10
(1)(4x-1)÷3-(x-2)÷6=(4+x)÷2
2(4x-1)-(x-2)=3(4+x)
8x-2-x+2=12+3x
4x=12
x=3
(2)x/3-x/5=4
5x-3x=60
2x=60
x=30
(3)(y+2)÷4-(y-3)÷5=10
5(y+2)-4(y-3)=200
5y+10-4y+12=200
y=178
2(4x-1)-(x-2)=3(4+x)
8x-2-x+2=12+3x
4x=12
x=3
(2)x/3-x/5=4
5x-3x=60
2x=60
x=30
(3)(y+2)÷4-(y-3)÷5=10
5(y+2)-4(y-3)=200
5y+10-4y+12=200
y=178
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