AB=AE,BC=ED,∠B=∠E,AF垂直CD于F,求证:CF=DF
如图,AB=AE,BC=ED,∠B=∠E,AF⊥CD于F.求证CF=DF.
如图,AB=AE,BC=ED,∠B=∠E,AF⊥CD于F.求证:CF=DF
已知,如图,ab=ae,bc=ed,∠b=∠e,af⊥cd,垂足为f.求证:cf=df 可画辅助
已知:如图,AB=AE,∠B=∠E,BC=ED,CF=DF.求证:AF⊥CD.
已知,如图,AB=AE,∠B=∠E,BC=ED,CF=DF,求证AF⊥CD
如图,已知AB=AE,BC=ED,∠B=∠E,AF⊥CD,F为垂足,试说明CF=DF.
如图,已知AB=AE,BC=ED,∠B=∠E,AF⊥CD,F为垂足,求证①AC=AD;①CF=DF
如图:已知AB=AE,BC=ED,∠B=∠E,AF⊥CD,F为垂足,求证:①AC=AD; ②CF=DF.
已知:如图,AB=AE,角B=角E,BC=ED,AF垂直于CD.求证:F是CD的中点
如图ab=ae,bc=ae 角bc=de 角b=角e cf=df 求证 af垂直cd
如图,已知AB=AE,BC=ED,AF⊥CD于F,CF=DF.
ab=cd,ae垂直于e,df垂直于bc于f,ad交ed于o,oa=od,求证:bf=ce