x-y+2=0,4x^2-y^2=12,怎么解
已知X.x+y.y-4x+2y+5=0,求4X.X-12X Y+9Y.y的值
已知x*x-4xy+4y*y=0 求[2x(x+y)-y(x+y)]/(4x*x-4xy+y*y)的值?
已知x*x+4x+y*y-2y+5=0,则x*x+y*y=?
解方程组x^2-y^2=x+y 4x^2-y^2+2x-y=0过程
解方程组:x+y/2+x-y/3=6 4(x+y)-5(x-y)=12
若(x*x+y*y)(x*x+y*y)-4x*x*y*y=0,求代数式(x*x+5xy+y*y)/(x*x+2xy+y*
x²+4y²-2x+12y+10=0求X,Y值
X+Y=5.7 1/4X+2/5Y=4/5X 怎么解
若|x+2y-1|+y²+4y+4=0,求(2x-y)²-2(2x-y)(x+2y)+(x+2y)&
已知x^2+4y^2-4x+4y+5=0,求(y^4-x^4)/(y-2x)(x+y)*2x-y
已知2x-y/x+3y=2,求代数式4x-2y/x+3y减4x+12y除以2x-y
已知2x-y/x+3y=2,求代数式4x-2y/x+3y减4x+12y/2x-y的值