tana=2,则2sin2a+1/sin2a=
求证:2(sin2a+1)/(1+sin2a+cos2a)=tana+1
证明 2(sin2a+1)/1+sin2a+cos2a=tana+1
证明tanA+cotA=2/sin2A
证明:(sin2a+1)/(sin2a+cos2a+1)=1/2(tana+1)
已知2sin2a+1=cos2a,求tana的值
已知(2sin^a+sin2a)/(1+tana)=k (0
化简sin2a(1+tana*tana/2)
求证:1+sin2a-cos2a/1+sin2a+cos2a=tana
求证1+sin2a-cos2a除以1+sin2a+cos2a=tana
若tana+1/tana=4,则sin2a
k=(2sin^2a+sin2a)/(1+tana) 则sin(a-3.14/4)的值
tanA+cotA=m,则sin2A=?