1.2009/1+2009/2+2009/3+.2009/2008= 2.2/1+4/1+8/1+16/1+.+1024
来源:学生作业帮 编辑:神马作文网作业帮 分类:数学作业 时间:2024/09/25 13:15:17
1.2009/1+2009/2+2009/3+.2009/2008= 2.2/1+4/1+8/1+16/1+.+1024/1=
2009/1+2009/2+2009/3+.2009/2008= 2/1+4/1+8/1+16/1+.+1024/1=
2009/1+2009/2+2009/3+.2009/2008= 2/1+4/1+8/1+16/1+.+1024/1=
楼主分数写法不对.楼上第2问回答错误,题目是有限数列,不是无限数列.
1.
1/2009+2/2009+3/2009+……+2008/2009
=(1/2009)*(1+2+3+……+2008)
=(1/2009)*{[2008*(2008+1)]/2}
=(1/2009)*(1004*2009)
=1004
2.
1/2+1/4+1/8+1/16+……+1/1024
=1/2+(1/2)^2+(1/2)^3+(1/2)^4+……+(1/2)^10
=(1/2)*{[1-(1/2)^10]/(1-1/2)}
=1-(1/2)^10
=1-1/1024
=1023/1024
1.
1/2009+2/2009+3/2009+……+2008/2009
=(1/2009)*(1+2+3+……+2008)
=(1/2009)*{[2008*(2008+1)]/2}
=(1/2009)*(1004*2009)
=1004
2.
1/2+1/4+1/8+1/16+……+1/1024
=1/2+(1/2)^2+(1/2)^3+(1/2)^4+……+(1/2)^10
=(1/2)*{[1-(1/2)^10]/(1-1/2)}
=1-(1/2)^10
=1-1/1024
=1023/1024
请问(2/2009+4/2009+6/2009+···+2008/2009)—(1/2009+3/2009+5/2009
1/2009×2/2009×3/2009×4/2009×5/2009×······×2008/2009怎么算?
1\2009+2\2009+3\2009.+2007\2009+2008\2009 = 为什么?
(-1*1/2)+(-1/2*1/3)+(-1/3*1/4)+.+(-1/2008*1/2009)+(-1/2009*1
|1/2-1|+|1/3-1/2|+1/4-1/3|+...|1/2009-1/2008|+|1/2010-1/2009
"1*2/1+2*3/1+3*4/1+.+2007*2008/1+2008*2009/1+2009*2010/1"这道题
1/1*2+1/2*3+1/3*4+1/4*5.+1/2007*2008+1/2008*2009=?
小学数学1/2009+2/2009+3/2009加到2007/2009+2008/2009怎样计算
(1+3+5+...+2009)-(2+4+6+...+2008)=?
1+2+3+4……+2008+2009+2010=?
1-2+3-4+5-6+...+2007-2008-2009=
(-1)+(+2)+(-3)+(+4)+...(-2007)+(+2008)+(-2009)+(20010)=