请问谁知道 log9(16)*log8(81)咋解?
求值:(log4^ 3+log8 ^9)*(log3^ 2+log9 ^16)
计算:(log4 9+log8 3)(log3 2+log9 2)-log1/3 4√81
化简:log8底27的对数×log9底25的对数×log5底16的对数
【(log4)^3+.(log8)^3】【.(log3)^2+.(log9)^2】=几啊
(1)log4 27乘以log25 8乘以log9 5 (2)(log4 3+log8 3)(log3 2+log9 2
计算(log4 3+ log8 3)(log3 2+ log9 2)-- log1/2 32^(1/3)+5^(log2
(log4 3+log8 3)(log3 2+log9 2)-log1/2 32^1/3+5^(log25 9)
(log2 3+log4 9+log8 27+...+log2^n 3^n)log9 32的N次方根
计算(log2 3+log4 9+log8 27+……+log2^n 3^n)log9 n次根号3
(log3 2)+log9 2)*(log4 3+log8 3)+(log3 3^1/2)^2+ln根号e-lg1
计算log9(根号2)*[log4(3)+log8(3)]
计算:(log4 3+log8 3)×log9 √2=?