ACM 斐波那切数列#include int fun(int n) { if(n==1) return 11; if(n
#include int fun(int*x,int n) { if (n==0) return x[0]; else
#include long fun(int n) {if(n>1) return (n*fun(n-1)); else
int fun(static int n) {if(n==1)return 1; else return(n+fun(n
一道C语言题,# include int fun (int n,int *s){int f1,f2;if (n==1||
这个代码的意思#include int f(int n){if (n == 1){return 1;}return f(
#includelong fun(int n){if(n>1)return (n*fun(n-1));return 1;
#include int ant(int n){ if (n>15) return (1,2); else return
int f(int m,int n) { if(m < n) return 0; if(n==0) return 1;
#include int fun(int n,int *s){int f1,f2;if(n==1IIn==2)*s=1;
int fac(int n) {if(n==0||n==1) return 1; else return n*fac(n
#include long fun(int n) {long s; if(n
double fact(int n) { if (n==0) return 1; else return n*(fact