如何消参x=(24t)/(5t^2-16t+32)y=(64-16t)/(5t^2-16t+32)
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如何消参
x=(24t)/(5t^2-16t+32)
y=(64-16t)/(5t^2-16t+32)
x=(24t)/(5t^2-16t+32)
y=(64-16t)/(5t^2-16t+32)
①②③④⑤⑥
1、x=(24t)/(5t^2-16t+32) ①
2x=(48t)/(5t^2-16t+32) ②
2、y=(64-16t)/(5t^2-16t+32) ③
3y=(192-48t)/(5t^2-16t+32) ④
3、② + ④得 2x+3y==192/(5t^2-16t+32) ⑤
②/④得 2x/3y=(48t)/(192-48t)=t/(4-t) ⑥
4、由⑥得
t=(8x)/(3y+2x) ⑦
将⑦代入⑤得
2x+3y=192/(5t^2-16t+32)
=192/{5[8x/(2x+3y)]^2-16[8x/(2x+3y)]+32}
化简后得14x²-52x-78y-12xy+9y²=0,此方程不含参数
1、x=(24t)/(5t^2-16t+32) ①
2x=(48t)/(5t^2-16t+32) ②
2、y=(64-16t)/(5t^2-16t+32) ③
3y=(192-48t)/(5t^2-16t+32) ④
3、② + ④得 2x+3y==192/(5t^2-16t+32) ⑤
②/④得 2x/3y=(48t)/(192-48t)=t/(4-t) ⑥
4、由⑥得
t=(8x)/(3y+2x) ⑦
将⑦代入⑤得
2x+3y=192/(5t^2-16t+32)
=192/{5[8x/(2x+3y)]^2-16[8x/(2x+3y)]+32}
化简后得14x²-52x-78y-12xy+9y²=0,此方程不含参数
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