x+y+z=4 2x-3y+4z=11

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x+y+z=4 2x-3y+4z=11
2x-y+z=3 3x+y-2z=3
3x-2y-3z=-5 z=x+y
这是三元一次方程,

x+y+z=4
2x-y+z=3
3x-2y-3z=-5
x =1,y= 1,z = 2
2x-3y+4z=11
3x+y-2z=3
z=x+y
x=2,y= -1,z =1
再问：要过程
再答： x+y+z=4 1 2x-y+z=3 2 3x-2y-3z=-5 3 (1)+(2)消去y 2（2）-（3）也消去y 然后再消去x或z x =1, y= 1, z = 2 2x-3y+4z=11 3x+y-2z=3 z=x+y 把z=x+y替换前2个等式，再消去x或y x=2, y= -1, z =1

x+2y+4z=17 2x+y+z=7 3x+y+2z=11 x=y/z=z/3,x+y+z ＝12,求2x+3y+4z是多少, x-y-z=-1 3x+5y+7z=11 4x-y+2z=-1 分别求出x=?y=?z=? 1.x+y=16,y+z=12,z+x=102.3x-y+z=4,2x+3y-z=12,x+y+z=63.x+y+z=6 试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y) (4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuai x+y+z=2 4x+2y+z=4 2x+3y+z=1 解方程：{2x+3y+z=7,x+y+z=4,3x+y-z=-4 解方程组1、4x+9y=12,3y-2z=1,2x+6z=32、3x-y+2z=3,2x+y-3z=11,x+y+z=1 x-y+4z=10,x+3y+2z=2,x+2y+3z=11. x+2y+3z=10,x-y+4z=10,x+3y+2z=2 x+y+z=4 2x+3y-z=6 3x+2y+2z=10