解[log(x-1)]²+2log(x-1)-3=0

已知log(1/7)[log(3)(log(2)x)]=0 解不等式:log½(x²-1)>log½(2x²-x-3) log底数7[log底数3（log底数2X）]=0,那么x^1/2的值是 解方程[log(a)(x-1)]-[log(a)(2x-3)]=log(a)(1/3-x),(a＞0,且a≠1). log(9)x+log(x^2)3=1的解为? log(X+5)+log(X+2)=1 1/log（2）x+1/log（3）x+1/log（4）x=1,x=? （高一）若x满足2(log(1/2)x)^2-14log(4)x+3≤0,求f(x)=[log(2)(x/2)]*{lo 已知log（2）[log（3)(log(4) x)] = log(3) [log(4) (log(2) y)]=0,求x log(2x)+log(3y)-log(2z) 怎么化简? log3(x^2-2x-6)=2 log(3x+6)=1+l 已知函数f(x)=log.(1-x)+log.(x+3)（0 2log底3x+log底3 2=1/2log底3 16 x为什么值