a1=1,an+1=an+2n 求an an+1 是在下面还是上面 请您讲解
数列{an},a1=1,an+1=2an-n^2+3n,求{an}.
a1=1/2,an+1=an/an+2,求n/an的sn
数列{an}中,a1=35,an+1-an=2n-1,求an
数列{an}满足a1=1,且an=an-1+3n-2,求an
已知数列{an}满足an+1=2an+3.5^n,a1=6.求an
已知A1=1,An=2An-1+n(n>1),求An.
设数列{an}中,a1=2,a(n+1)=an+n+1,求an
数列an,a1=4,an+1=5^n*an,求an
在数列{an}中,a1=1,2an+1=(1+1/n)^2*an,证明:数列{an/n^2}是等比数列,并求an的通项公
已知数列an满足:an+1-2an=2^n+1,且a1=2 (1)证明{an/2^n}是等差数列 (2)求数列an的
数列{an}满足a1=1 an+1=2n+1an/an+2n
已知数列{an}满足a1=1/2,an+1=an+1/n的平方+n求an