(1)(-2a^3)^4/a^6/(a^3)^2 (2)(12a^3b^2-6a^2b-3ab)/(-3ab)
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(1)(-2a^3)^4/a^6/(a^3)^2 (2)(12a^3b^2-6a^2b-3ab)/(-3ab)
(3)[x(x^2y^2-xy)-y(x^2-x^3y)]/3x^2y,其中x=-1,y=1
(3)[x(x^2y^2-xy)-y(x^2-x^3y)]/3x^2y,其中x=-1,y=1
(1)
(-2a^3)^4/a^6/(a^3)^2
=16a^12/a^6/a^6
=16a^(12-6-6)
=16a^0
=16*1
=16
(2)
(12a^3b^2-6a^2b-3ab)/(-3ab)
=3ab(4a²b-2a-1)/(-3ab)
=-4a²b+2a+1
(3)
[x(x^2y^2-xy)-y(x^2-x^3y)]/(3x^2y)
=[(x³y²-x²y)-(x²y-x³y²)]/(3x²y)
=(-2x²y)/(3x²y)
=-2/3
取值与xy的值无关
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(-2a^3)^4/a^6/(a^3)^2
=16a^12/a^6/a^6
=16a^(12-6-6)
=16a^0
=16*1
=16
(2)
(12a^3b^2-6a^2b-3ab)/(-3ab)
=3ab(4a²b-2a-1)/(-3ab)
=-4a²b+2a+1
(3)
[x(x^2y^2-xy)-y(x^2-x^3y)]/(3x^2y)
=[(x³y²-x²y)-(x²y-x³y²)]/(3x²y)
=(-2x²y)/(3x²y)
=-2/3
取值与xy的值无关
【中学生数理化】团队为您答题,祝你学习进步!
有不明白的可以追问!如果您认可我的回答.
请点击下面的【选为满意回答】按钮.
计算(3a-2b)(9a*a+6ab+4b*b)-(3a+2b)(9a*a-6ab+4b*b)
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