(x+y)^2(x-y)^2(x^4+x^2y^2+y^4)=?
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(x+y)^2(x-y)^2(x^4+x^2y^2+y^4)=?
(x+y)^2(x-y)^2(x^4+x^2y^2+y^4)
= { (x+y) (x-y) }^2 (x^4+x^2y^2+y^4)
= ( x^2-y^2 )^2 (x^4+x^2y^2+y^4)
= ( x^2-y^2 ) { ( x^2-y^2 ) (x^4+x^2y^2+y^4) }
= ( x^2-y^2 ) { ( x^2)^3 - (y^2) ^3 }
= ( x^2-y^2 ) ( x^6-y^6 )
= x^(2+6) - x^6y^2 - x^2y^6 + y^(2+6)
= x^8 - x^6y^2 - x^2y^6 + y^8
= { (x+y) (x-y) }^2 (x^4+x^2y^2+y^4)
= ( x^2-y^2 )^2 (x^4+x^2y^2+y^4)
= ( x^2-y^2 ) { ( x^2-y^2 ) (x^4+x^2y^2+y^4) }
= ( x^2-y^2 ) { ( x^2)^3 - (y^2) ^3 }
= ( x^2-y^2 ) ( x^6-y^6 )
= x^(2+6) - x^6y^2 - x^2y^6 + y^(2+6)
= x^8 - x^6y^2 - x^2y^6 + y^8
x^2-y^2/x+y-4x(x-y)+y^2/2x-y,
(2x-y)^2-4(x-y)(x+2y)
(2x-y)²-4(x-y)(x+2y)
化简:(2x-y)²-4(x-y)(x+y)
{(z+y)(x-y)-(x-y)的2次方+2y(x-y)}除以4y
已知4x=9y求(1)x+y/y (2)y-x/2x
{3(x+y)-4(x-y)=4 {x+y/2 + x-y/6=1
x+y/2+x-y/3=6,4(x+y)-3(x-y)=-20
{(x+y)/2+(x-y)/3=6 4(x+y)-3(x-y)=-20
3(x+y)-4(x-y)=11,2(x-y)+5(x+y)=27
4(x+y)-3(x-y)=-20,2/x+y+3/x-y=6
(x+y)(x+2y)(x+3y)(x+4y)=-40