log2(√2-1)-log2((√2+1)=log2(x^2)
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log2(√2-1)-log2((√2+1)=log2(x^2)
求x+(1/x)的值
(PS,log后的2是底数,括号里的都是N,希望有过程.
求x+(1/x)的值
(PS,log后的2是底数,括号里的都是N,希望有过程.
要使log2(√2-1)-log2((√2+1)=log2(x^2) 有意义,X^2>0,即X>0,
log2(√2-1)-log2((√2+1)=log2(x^2)
log2[(√2-1)/(√2+1)]=log2(x^2)
(√2-1)/(√2+1)=x^2,
x^2=(√2-1)^2,(x>0)
x=(√2-1),
x+(1/x))的值=(√2-1)+1/(√2-1)=2√2.
log2(√2-1)-log2((√2+1)=log2(x^2)
log2[(√2-1)/(√2+1)]=log2(x^2)
(√2-1)/(√2+1)=x^2,
x^2=(√2-1)^2,(x>0)
x=(√2-1),
x+(1/x))的值=(√2-1)+1/(√2-1)=2√2.
解方程log2(2-x)=log2(x-1)+1
log2 (x + 3) + log2(x + 2) = 1
log2(√1/48)+log2 12-1/2log2 (24)-1/3
log2底√1/48+log2底12-1/2log2底24等于?
Log2√(7/48) +log2 12 -(1/2)log2 42
log2 SQR(7/48)+log2 12 -1/2log2 48
log2 SQR(7/48)+log2 12 -1/2log2 42
不等式log2(2x+3)>log2(x+1)的解集是
不等式log2(x^2-1)
已知函数f(x)=log2(2-x)+log2(2+x),g(x)=log2(2x-1)
log2(根号下7/48)+log2(12)-1/2log2(42)-1=?
|2x-log2^x|