Barts and Lisa play a game.Bart has one die and Lisa has two

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Barts and Lisa play a game.Bart has one die and Lisa has two.They each take one roll.What is the
question about probability
Barts and Lisa play a game.Bart has one die and Lisa has two.They each take one roll.What is the probability that the number Bart rolls is higher than the sum of Lisa‘s dice？

问题没问完..
问题翻译是：“巴特和丽萨在玩游戏,巴特有一个色子,丽萨有两个.他们分别要一次,问..”之后就没了
再问：不好意思..我当然知道题意，我是反应不过来怎么做了... Barts and Lisa play a game. Bart has one die and Lisa has two. They each take one roll. What is the probability that the number Bart rolls is higher than the sum of Lisa‘s dice？
再答： probability = event/outcome, in this case, for Bart has greater number, Bart can have 3, while Lisa has 2, Bart can have 4, Lisa has 2 or 3, Bart has 5, Lisa has 2, 3, or 4, Bart has 6 and Lisa has 2, 3, 4, or 5. So the total event would be 1+2+3+4 = 10. For outcome, each time Bart rolls Lisa can have 2, 3, 4, 5, till 12, there would be 12 outcome each time Bart rolls, and Bart can roll 1,2, 3 or ..till 6, so the total outcome would be 6x11 = 66 probability therefore = 10/66 = 5/33
再问：你跟我算出来的一样...可以我考试老师给的叉叉... 答案是10/216
再答：哦对了，outcome是6x6x6,因为bart可以扔1到6，然后lisa第一个可以扔1到6，第二个也可以扔1到6,所以是10/6x6x6 = 10/216

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