如图,AE=AF,角AEF=∠AFE,BE=CF,说明AB=AC
如图,AE=AF,BE⊥AC,CF⊥AB.CF、BE交于O.求证∠BAO=∠CAO
如图,已知在△ABC和△AEF中,AB=AC,AE=AF,∠CAB=∠EAF,BE交FC于O点.
如图,在三角形ABC中,AB=AC,E在CA的延长线上,∠AEF=∠AFE,试说明EF⊥BC.
已知如图在△ABC中,AB=AC,E在CA的延长线上,∠AEF=∠AFE.试说明EF⊥BC
如图,三角形ABC相似三角形AEF.求证:AB乘以CF=AC乘以BE
如图,三角形ABC中,BE垂直于AC与E,CF垂直于AB与F,试说明角AEF=角ABC
如图所示,已知AE垂直于AB,AF垂直于AC,AFE=AB,AF=AC,说明EC垂直于BF
AB=AC CF垂直BC BE垂直BC 求证 AE=AF
如图,在△ABC和△AEF中,AB=AC,AF=AE,∠BAC=∠EAF,FC、BE交于M,连接AM,当∠BAC=90·
如图,在△ABC中,AB=AC,EF为过点A的任一直线,CF⊥BC,BE⊥BC,求证:AE=AF
如图,AB‖CD,AD‖BC,AE⊥AB,AF⊥AD,AE=AB,AF=AD,试说明AC=EF
△ ABC的周长为100cm,如图AE/AB=AF/AC=EF/BC=3/5,△ AEF的周长为________