计算:9^(log3 2)-2^(1+1/2log2 5)
log2(3)+log3(5)+log3(2)=?
计算(1/8)的-2/3次方+(log2 9).(log3 4)
1.9^log3(2)-2^[1+1/2log2(5)]
log2(2)+log5(1)-log1/3(1/27)+[3^log3(5)]^2+3^-log3(2)=?
(log3 4+log3 8)(log2 3+log2 9)+(log3 根号2)(log9 7)/(log1/3 7)
计算log2 6-log2 3,lg5+lg2,log5 3+log5 1/3,log3 5-log3 15
计算log3[(9^2 * 27^(1/3))/3^(log3 234)]
计算(log4 3+ log8 3)(log3 2+ log9 2)-- log1/2 32^(1/3)+5^(log2
计算:lg(1/2)-lg(5/8)+lg(12.5)+log2为底3*log3为底8=
log的计算 :log2(20)-log4(25)= log3(2)×log2(5)×log5(3)=?log2[log
log2(20)-log2(5)+2log3(2)×log4(3)
(log3^4+log5^2)(log2^9+log2^根号3)