lim(2nan)=1,且liman存在,则lim[(1-n)an]=
lim2nan=1(n→∞),且liman(n→∞)存在,则lim(1-n)an(n→∞)=多少
极限的运算法则!已知 lim(2n+1)an=3,lim(nan)=
设级数∑An收敛,且lim(nAn)=a,证明∑n(An-A(n+1))收敛
若liman=a,则lim|an|=|a|
若极限LIM[(3N+1)*AN]=1,求LIM(NAN)的极限 答案为1/3.
已知数列{An}与{Bn}都是公差不为零的等差数列,且limAn/Bn=2,求lim(A1+A2+……+An)/(n*B
已知数列an是等差数列,且a1≠0,Sn为这个数列的前n项和.求1、lim nan/Sn 2、lim (Sn+Sn+1)
证明若pk>o(k=1,..)lim[pn/p1+p2+……+pn]=0,liman=a则lim{[p1an+p2a(n
若liman=a求证lim[(a1+a2···+an)/n]=a
设limAn=a,limBn=b,试证明:lim{(A1*Bn+A2*Bn-1+...+An*B1)\n}=ab (n-
已知数列{an}满足lim[(2n-1)an]=2,则lim(n+2)an=
若lim[(2n-1)an]=1 求lim(n*an)的值