cos(a-b)=-12/13,cos(a+b)=12/13,a-b(π/2,π),a+b(3π/2,2π)cos2a,
来源:学生作业帮 编辑:神马作文网作业帮 分类:数学作业 时间:2024/11/14 22:14:07
cos(a-b)=-12/13,cos(a+b)=12/13,a-b(π/2,π),a+b(3π/2,2π)cos2a,cos2b,b=?
a-b(π/2,π),a+b(3π/2,2π) cos(a-b)=-12/13,cos(a+b)=12/13
sin(a-b)=5/13 sin(a+b)=-5/13 2b(π/2,3π/2)
cos=cos(a-b+a+b)= cos(a-b)cos(a+b)-sin(a-b) sin(a+b)=119/169
cos2b=cos(-2b)=c0s(a-b-(a+b))=1
b=π/2
sin(a-b)=5/13 sin(a+b)=-5/13 2b(π/2,3π/2)
cos=cos(a-b+a+b)= cos(a-b)cos(a+b)-sin(a-b) sin(a+b)=119/169
cos2b=cos(-2b)=c0s(a-b-(a+b))=1
b=π/2
已知cos(a-b)=-12/13 cos(a+b)=12/13且π/2
已知sin(a+b)=-3/5,cos(a-b)=12/13,且π/2
已知:锐角A,B满足cos(A+B)=1/2,sin(A-B)=1/3,求cos2A
已知cos(a+b)=0,求值:sin(π+2a+b)-cos(-π/2+2a+3b)
已知sin(a+2b)=4/5,cos(a+b)=12/13(a+2b,a+b)属于(0~2π)求sinb
已知COS(A+B)=12/13,COS(2A+B)=3/5,若A∈(0,π/2),求COSA的值
a,b为锐角,cos(a+b)=12/13 cos(2a+b)=4/5 求cosa
求证sin平方a * sin平方b+cos平方a * cos平方b-1/2cos2a *cos2B=1/2
cos(a-b)=12/13,sin(a+b)=-3/5,求cos(pai/2-2a)
已知π/2<B<A<3π/4,cos(A-B)=12/13,sin(A+B)=-3/5,求sin2A
已知π/4<a<b<π/2,且sin(a+b)=4/5,cos(a-b)=12/13
已知三角型abc三内角a b c 成等差数列,且a-c=π/3,求cos^2a+cos^2b+cos^c的值