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来源：学生作业帮编辑：神马作文网作业帮分类：数学作业时间：2024/11/12 22:11:59

解题思路：利用勾股定理的逆定理，由三角形的三边长可得△ABC为Rt△，根据90°的圆周角所对的弦为直径得出EF为圆的直径，又圆与AB相切，设切点为D，可知当CD⊥AB时，根据点到直线的垂线段最短可得CD最短，此时EF亦最小，由三角形ABC为直角三角形，根据直角三角形的三边长，利用面积法即可求出CD的长，即为EF的最小值．
解题过程：
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最终答案：略

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