设f(0)=1,f(2x)=f(x)cos²x,当x→0时,f(x)→f(0)求f(x)

f(x)有定义,f(2x)=f(x)cos x,lim f(x)=f(0)=1(x趋于0时),求f(x) 设2f(x)cos x=d/dx [f(x)]²,f(0)=1,则f(x)= 设F（x）为f(x)的原函数,当x≥0时,有f(x)F(x)=(sin2x)^2,且F(0)=1,F(x)≥0,求f(x 设f(x)为奇函数,且当x>0时,f(x)=log1/2x.(1)求当x 设函数f(x)满足f(x)+2f(1/x)=x,求f(x) 设函数.F（x）={x-1,x0.当x→0时,求F(x)的极限 设F(x)的导数=f(x),当x》0时,有f(x)F(x)=sin2x的平方,且F(0)=1 , F(X)》0,求f(x 设f(x)有二阶导数,且f''(X)>0,lim(x趋于0）f(x)/x=1 ..证明：当x>0时,有f(x)>x ①设f(x)=x+2∫(0,1)f(t)dt,求f(x). f(x)定义在(0,+无穷大) 当x>1时 f(x)>0,且f(xy)=f(x)+f(y) 解不等式f[x(x-1/2) 设f=[sin(2/x)]=1+cosx,求f(x),f[cos(2/x)]. 设函数f(x)满足f(x)+2f=x(x不等于0),求f(x)