1/（1x3）+1/（2x4）+1/（3x5）+1/(4x6)+1/(5x7)+1/(6x8)的答案

来源：学生作业帮编辑：神马作文网作业帮分类：数学作业时间：2024/11/11 01:26:04

1/(1x3)+1/(2x4)+1/(3x5)+1/(4x6)+1/(5x7)+1/(6x8)
=[1/(1*3)+1/(2*4)+1/(3*5)+1/(4*6)+1/(5*7)+1/(6*8)]*[2*(1/2)]
=[2/(1*3)+2/(2*4)+2/(3*5)+2/(4*6)+2/(5*7)+2/(6*8)]*(1/2)
=[(1-1/3)+(1/2-1/4)+(1/3-1/5)+(1/4-1/6)+(1/5-1/7)+(1/6-1/8)]*(1/2)
=1+1/2-1/7-1/8
=153/56

x8+x7+x6+x5+x4+x3+x2+x+1因式分解计算：1/1x2+1/2x3+1/3x4+1/4x5+1/5x6+1/6x7+1/7x8+1/8x9+1/9x10. 2x2/1x3+4x4/3x5+6x6/5x7+8x8/7x9+10x10/9x11+12x12/11x13 仔细看看 1.如果1+X+X2+X3=0,求X+X2+X3+X4+X5+X6+X7+X8的值为? 一道数学题:如果1+x+x2+x3=0,求x+x2+x3+x4+x5+x6+x7+x8的值 1x2/1+2x3/1+3x4/1+4x5/1+5x6/1+6x7/1 1/1x2+1/2x3+1/3x4+1/4x5+1/5x6+1/6x7 (2X2)/1X3+(4X4)/(3X5)+(6X6)/(5X7)+...+(20X20)/(19X21)==? 某同学做一道数学题：当x=-1时，求10x9+9x8+8x7+7x6+6x5+5x4+4x3+3x2+2x+1的值，由于小明做一道数学题，“求代数式10x9+9x8+8x7+7x6+6x5+5x4+4x3+3x2+2x+1，当x=-1时的值某同学在做一道题：求代数式10x9+9x8+8x7+7x6+6x5+5x4+4x3+3x2+2x+1当x=-1时的值．由（1x2+2x4+3x6+4x8）/（2x3+4x6+6x9+8x12)