log3*2/log9*4=?
(log3 4+log3 8)(log2 3+log2 9)+(log3 根号2)(log9 7)/(log1/3 7)
[log2(3)+log4(9)][log3(4)+log9(2)]等于
(log3^2 + log9^4)×(log4^3 + log8^3)
log 243÷log9 =log3^5÷log3^2 =log3^5-log3^2 然后怎么写
(log2(3)+log8(9))x(log3(4)+log9(8)+log3(2))
(log2 3+log8 9)(log3 4+log9 8+log3 2)的运算过程
log3 5-log3 15+1/2log9 27 的值
求x,y值.6log9^x+3log27^y=8log3^x+2log9^y=2
由换底公式怎么得到log9(x+5)=log3[2(x+5)]=1/2log3(x+5)
1.log2 3*log3 4*log4 5*log5 2 2.(log4 3+log8 3)8(log3 2+log9
(log3,4+log9,4)log4,3—log2,2根号2 这怎么解答了
计算:(log4 9+log8 3)(log3 2+log9 2)-log1/3 4√81