有关本征矢量问题a [I-P]=0, I is identity matrix. Then, a is an eigen

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有关本征矢量问题
a [I-P]=0, I is identity matrix. Then, a is an eigenvector of P, associated with the eigenvalue m=1
以上这句话怎么理解（非翻译）?a [I-P]=0 是本征矢量的定义式吗?
另外,P=(P11=0.7,P12=0.3,P21=0.6,P22=0.4), 从而可以求出 a=(a11=2/3, a12=1/3)
这怎么求出来的呀?

你这是老外的教材上来的?
有点晕了,难道特征向量的定义不一样?!
若是 (I-P)a=0 我还可以解释.
此时 Pa = 1a,若a≠0,则 1是P的特征值,a是P的属于特征值m=1的特征向量.
你还是按教材上的定义理解吧.
我试乘了一下 [2/3,1/3]P 果然等于 [2/3,1/3]
即有 [2/3,1/3](I-P)=0
再问：非常感谢！但是为什么我不能用1减去P的各项值，求出I-P矩阵，然后再根据a [I-P]=0或 (I-P)a=0 来计算a的值呢？我这么试了一下，算出来a值为0。不知道是算错了，还是不能这么算。
再答：不能用1减去P的各项值, 只有主对角线是, P的其余元素取相反数

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