(1+0.228-0.21)×(0.228-0.21+0.2003)-(1+0.228-0.21+0.2003)×(0.
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(1+0.228-0.21)×(0.228-0.21+0.2003)-(1+0.228-0.21+0.2003)×(0.228-0.21)
简便运算,要写出具体过程
简便运算,要写出具体过程
设1+0.228-0.21=x 0.228-0.21=y
原式=x*(y+0.2003)-(x+0.2003)*y
=xy+0.2003x-xy-0.2003y
=0.2003x-0.2003y
=0.2003*(x-y)
=0.2003*1
=0.2003
再问: 用数学方法哩!
再答: 实际上面的就是代数方法 (1+0.228-0.21)×(0.228-0.21+0.2003)-(1+0.228-0.21+0.2003)×(0.228-0.21) = (1+0.228-0.21)×(0.228-0.21)+(1+0.228-0.21)×0.2003-(1+0.228-0.21)×(0.228- 0.21)-0.2003×(0.228-0.21) =(1+0.228-0.21)×0.2003-0.2003×(0.228-0.21) =(1+0.228-0.21-0.228+0.21)×0.223 =1×0.2003 =0.2003
原式=x*(y+0.2003)-(x+0.2003)*y
=xy+0.2003x-xy-0.2003y
=0.2003x-0.2003y
=0.2003*(x-y)
=0.2003*1
=0.2003
再问: 用数学方法哩!
再答: 实际上面的就是代数方法 (1+0.228-0.21)×(0.228-0.21+0.2003)-(1+0.228-0.21+0.2003)×(0.228-0.21) = (1+0.228-0.21)×(0.228-0.21)+(1+0.228-0.21)×0.2003-(1+0.228-0.21)×(0.228- 0.21)-0.2003×(0.228-0.21) =(1+0.228-0.21)×0.2003-0.2003×(0.228-0.21) =(1+0.228-0.21-0.228+0.21)×0.223 =1×0.2003 =0.2003
(1+0.21+0.32)*(0.21+0.32+0.43)-(1+0.21+0.32+0.43)*(0.21+0.32
计算(1+0.21+0.32)x(0.21+0.32+0.43)-(1+0.21+0.32+0.43)x(0.21+0.
(1+0.21+0.32)*(0.21+0.32+0.43)-(1+0.21+0.32+0.43)*(0.21+0.32
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