求outtextxy(x-12,y 20*i,"\4");if(!((body[0].x-1==body[2].x

1 int x=1,y=0; 2 if(!x) y++; 3 else if(x==0) 4 if(x) y+=2; 5 int x=1,y=0; if(!x)y++; else if(x==0) if(x)y+=2; else y+=3; 求x²+y²-2x+4y+1的最小值 求x,y的值 x²+2xy+4x-12y+22=0 已知4x=9y求(1)x+y/y (2)y-x/2x 已知X.x+y.y-4x+2y+5=0,求4X.X-12X Y+9Y.y的值 已知x*x-4xy+4y*y=0 求[2x(x+y)-y(x+y)]/(4x*x-4xy+y*y)的值? x²+4y²-2x+12y+10=0求X,Y值 已知方程组4x+2y=1,20x+8y,求x,y 求y=(5x-1)/(4x+2) (x 若|x+2y-1|+y²+4y+4=0,求（2x-y）²-2（2x-y)(x+2y)+(x+2y)& 下面程序表示的函数解析式是,if x>0,then y=2^x+1,else y=x*x+2*x,end if,prin #includemain(){int x=1,y=2,z=3;if(x>y)if(y